Question

G(t)=-3t^2+2t-5 and h(t)=4t+3

Find:
h(t)-g(t) , g(3)+h(3) , (g-h)(2) , g(-1)-h(2) , (g•h)(3) , g(2)+h(4) , g(1)•h(-1)

Answer 1

If this is the problem

g(t) = t2 - 3t and h(t) = 3t - 4

g[ h(t) ] = (3t-4)2 - 3 (3t-4)

g[ h(t) ] = 9t2 - 24t + 16 - 9t + 12

g[ h(t) ] = 9t2 - 33t + 28