Question

Given that cot A = 16/63 and that angle A is in Quadrant I, find the exact value of cscA in simplest radical form using a rational denominator.

Answer 1

Below in bold.

Explanation:

cot = adjacent side / opposite side = 16/63

So the hypotenuse = √(16^2 + 63^2)

= √4225

= 65.

So csc A = hypotenuse /opposite side

= 65/63