Question

PLEASE HELP ME WITH THIS ONE QUESTION

A photon has 2.90 eV of energy. What is the photon’s wavelength? (h = 6.626 x 10^-19, 1 eV = 1.6 x 10^-19 J)

A) 677 nm

B) 218 nm

C) 345 nm

D) 428 nm

Answer 1

The correct option is D.

Step-by-step explanation:

The wavelength of the photon can be calculated with the following equation:

`E = h(c)/(\lambda)`

Where:

E: is the energy of the photon = 2.90 eV

h: is the Planck's constant = 6.62x10⁻³⁴ J.s

c: is the speed of light = 3x10⁸ m/s

λ: is the wavelength

Hence, the photon's wavelength is:

`\lambda = (hc)/(E) = (6.62 \cdot 10^(-34) J*s*3.0 \cdot 10^(8) m/s)/(2. 90 eV*(1.6 \cdot 10^(-19) J)/(1 eV)) = 428 nm`

Therefore, the correct option is D.

I hope it helps you!