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The PH of a solution with a [H+] of 1x10^9 is ?

The PH of a solution with a [H+] of 1x10^9 is ?
asked 46.1k views
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The PH of a solution with a [H+] of 1x10^9 is ?

asked
User Ayano
by
7.9k points

1 Answer

3 votes

Answer:

9

Step-by-step explanation:

pH = -log[H+] = -log(1x10^9) = 9

answered
User Bharat Bhushan
by
8.3k points
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