Question

In ΔFGH, the measure of ∠H=90°, FH = 8, OF = 17, and HG = 15. What ratio represents the sine of ∠G?

Answer 1

`\sin(G) = (8)/(17)`

Explanation:

Given

`\angle H = 90^o`

`FH = 8`

`GF = 17`

`HG = 15`

See attachment for illustration

Required

The ratio of
`\sin(G)`

`\sin(G)` is calculated as:

`\sin(G) = (Opposite)/(Hypotenuse)`

From the attachment, we have:

`\sin(G) = (FH)/(GF)`

This gives:

`\sin(G) = (8)/(17)`