Question

How many total atoms are there in 60.3 g of carbon monoxide (CO)?
total atoms:
atoms

Answer 1

Step-by-step explanation:

moles = mass/mr

=60.3/28

=2.15 moles

number of particles = moles × 6.02×10^23

= 2.15×6.02×10^23

= 1.29×10^24 atoms

CO=12+16=28