Question

2logb - 3logb = log8b - log4b​

Answer 1

b=1/2

Explanation:

2logb - 3logb = log8b - log4b

log
`b^(2)` - log
`b^(3)` = log8b - log4b

log(
`(1)/(b)`) = log(2)

∴1/b = 2

∴b = 1/2