Question

A rock is thrown horizontally from a height of 6.00 m. Which of the following is the time required for the rock to reach the ground ?

Answer 1

t=10.95 seg

Step-by-step explanation:

The vertical component of velocity is 0, so, the time in air can be calculated

`h=v_ot-(1)/(2)gt^2\\\\h=0-(1)/(2)gt^2~=>t=√(2gh)=\sqrt{2*10(m)/(s^2)*6m}=10.9544~seg`