Question

At what temperature will 0.371 moles of neon gas occupy 10.30L at 2.50 atm?

Answer 1

T=846K

Step-by-step explanation:

We can use the formula for the Ideal Gas Equation, which is

`PV=nRT`

P=pressure

V=volume

n=mols of gas

R=constant (0.08201 L-atm/mol-K)

T=temperature

We will have to rearrange to equation to find temperature, which is

`T=(PV)/(nR)`

Time to solve:

`T=((2.50 atm)(10.30L))/((0.371 mols)(0.08206 L-atm/mol-K))`

`T=846 K`

If you want to convert to Celsius, subtract 273 to your answer, which will get you 573ºC.