Question

a block is pulled 0.90m to the right in 2.4s what is the blocks average speed to the nearest hundredths of m/s

Answer 1

`0.38\:\mathrm{m/s}`

Explanation:

Average velocity is given by
`v=(\Delta x)/(\Delta t)`, where
`\Delta x` is displacement and
`\Delta t` is change in time.

What we know:

• 
  `\Delta x` is
  `0.90\:\mathrm{m}`
• 
  `\Delta t` is
  `2.4\:\mathrm{s}`

Solving for
`v`:

`v=(0.90)/(2.4)=0.375\approx\boxed{0.38\:\mathrm{m/s}}`