Question

A ball is dropped from rest out of a high window in a tall building for 5 seconds. Assuming we ignore air resistance and assume upwards to be positive. A) What will be the final velocity of the ball B) What is the height of the building if it hits the ground after those 5 seconds.

Answer 1

final velocity=-49m/s and height=122.5

Step-by-step explanation:

u=0,t=5s,v=?

v=u+gt

v=0+(-9.8)5

v=-49m/s

h=ut+1/2gt*2

h=0(5)±1/2(-9.8)5*2

h=-122.5 or 122.5

but height=122.5 because height cannot be negative

Answer 2

what is the upwards force?