In the laboratory a student finds that it takes 103 Joules to increase the temperature of 12.6 grams of solid diamond from 22.4 to 39.4 degrees Celsius. The specific heat of dia…

Question

asked May 13, 2022 121k views

1 Answer

Artoon · Answer 1 · 2022-05-20T05:06:21+0000

Answer:

The correct solution is "
$0.480 \ J/g^(\circ)C$ ".

Step-by-step explanation:

Given:

q = 103 J

Mass,

m = 12.6 grams

Temperature,

T_1=22.4

T_2=39.4

$\Delta T=T_2-T_1$

=39.4-22.4

$=17^(\circ)C$

Now,

⇒
$C=(q)/(m* \Delta T)$

⇒
=(103)/(12.6* 17)

⇒
=(103)/(214.2)

⇒
$=0.480 \ J/g^(\circ)C$