Question

Solve 2x^2
+ x - 4= 0.
x2 +
= 0
DONE

Answer 1

`\\ \sf\longmapsto 2x^2+x-4=0`

`\\ \sf\longmapsto 2x^2+x=4`

`\\ \sf\longmapsto 8(2x^2+x=4)`

`\\ \sf\longmapsto 16x^2+8x=32`

`\\ \sf\longmapsto (4x)^2+2(4x)(1)=32`

`\\ \sf\longmapsto 4x^2+2(4x)(1)+1^2=32+1^2`

`\\ \sf\longmapsto (4x+1)^2=33`

`\\ \sf\longmapsto 4x+1=\pm√(33)`

`\\ \sf\longmapsto 4x=-1\pm√(33)`

`\\ \sf\longmapsto x=(-1\pm√(33))/(4)`