asked 190k views
2 votes
Let e be the line through A (-4,5) and B (3. t) that is perpendicular to the line through

P (1, 3) and Q(-4, 2). Find the value of t.



Let l be the line through A (4, -3) and B (t, -2) that is parallel to the line through
P(-2, 4) and Q (4, -1). Find the value of t.



Determine the signs of sino coso and tane if O is an angle in standard position and
P (2,-5) is a point on its terminal side.​

asked
User Tdube
by
7.7k points

1 Answer

4 votes

Answer:

Explanation:

product of slopes of perpendicular lines=-1

(t-5)/(3+4)×(2-3)/(-4-1)=-1

(t-5)/7×(-1/-5)=-1

(t-5)/35=-1

t-5=-1×35=-35

t=-35+5

t=-30

2.

slopes of parallel lines are equal.

(-2+3)/(t-4)=(-1-4)/(4+2)

1/(t-4)=-5/6

t-4=-6/5

t=4-6/5=(20-6)/5=14/5

3.

x>0,y<0

so P lies in4th quadrant.

except cos and sec all are negative.

so only cos and sec are positive.

answered
User Marc Abramowitz
by
7.3k points

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