asked 150k views
4 votes
Write a function rule for the area A(h) of a parallelogram whose base is 3 units more than its height h.

A. A(h) = h2 + 3
B. A(h) = h2 + 3h
C. A(h) = h2 + 3h + 3
D. A(h) = h + 3h

asked
User Dunadar
by
8.6k points

1 Answer

1 vote

Answer: h^2+3h (Choice B)

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Work Shown:

height = h

base = h+3, since the base is 3 more than the height

area = base*height

area = h*(h+3)

area = h*h + h*3

area = h^2+3h

answered
User Dursk
by
7.3k points

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