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Please factor and find the zeros of each relation. (19 marks)

E. y = 3x^2 + 12x
F. y = x^2 + 20x + 100

1 Answer

1 vote

Answer:

Explanation:

y=3x^2+12x = 3x (x+4)

zeroes: x={0, -4}

y = x^2+20x+100 = (x+10)^2

zeroes: x = -10 (twice)

or x={-10, -10}

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User RHarrington
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