Question

. A tennis ball rolls off the lab bench with an initial velocity of 3.0 m/s. The top of the lab bench is 1.5 m above the floor. How long will the tennis ball be in the air before it hits the ground

Answer 1

`{ \huge{s}} = ut + (1)/(2) g {t}^(2) \\ 1.5 = 3t + (1)/(2) * 10* {t}^(2) \\ 1.5 = 3t + 5 {t}^(2) \\ 5 {t}^(2) + 3t - 1.5 = 0 \\ t = 0.3 \: seconds`