Question

A bag contains 8 apples and 6 oranges. You randomly draw a piece of fruit from the bag, eat it, and than randomly draw another. What is the probability you draw and eat an apple than draw an orange?

Answer 1

`probability \ of\ choosing\ apple\ first = (8)/(14)\\\\probability\ of\ choosing\ orange\ second = (6)/(13)\\\\probability \ of \ choosing \ apple \ and \then \ orange = (8)/(14) *(6)/(13) = (24)/(91)`