Question

To print tickets, a printer charges a $30 setup fee plus $1.05 per ticket. Write an algebraic expression for the cost of t tickets. What is the cost of 300 tickets?

an explanation 2 plz thx

Answer 1

Solution given:

we have

setup price =$30

as rate for 1 print tickets =$1.05/tickets

so

for t

t=$30+$1.05*t

is a required expression.

the

cost of 300 tickets:

300 tickets =$30+$1.05*300=$345

$345is the cost of 300 tickets.