Question

The zeros of a parabola are 6 and -5. If (-1, 3) is a point on the graph, which equation can be solved to find the

value of a in the equation of the parabola?
O3 = a(-1 + 6)-1-5)
O 3 = a(-1-6)(-1 +5)
O -1 = a(3+6)(3-5)
O-1 = a(3-6)(3+5)

Answer 1

3 = a(-1-6)(-1+5).

Explanation:

y = a(x - 6)(x + 5)

When x = -1, y = 3 so we have:

3 = a(-1-6)(-1+5).