Question

In the diagram, q1 = -3.33*10^-9 C and

q2 = -5.22*10^-9 C. The electric field at
point P is zero. What is the distance
from P to q2?

Answer 1

The distance will be "0.319 m".

Step-by-step explanation:

The diagram of the given question is not attached with the problem. Below is the attached figure.

The given values are:

`q1 = -3.33* 10^(-9) \C`

`q2 = -5.22* 10^(-9) \ C`

As we know,

The electric field will be equivalent as well as opposite throughout the direction, then

⇒
`(R.q1)/((0.255)^2) =(R.q2)/(r^2)`

⇒
`r^2=(q2)/(q1)* (0.255)^2`

By putting the values, we get

⇒
`=(-5.22* 10^(-9))/(-3.33* 10^(-9))* (0.255)^2`

⇒
`=1.568* 0.065`

⇒
`r^2=0.10193`

⇒
`r=√(0.10193)`

⇒
`0.319 \ m`