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In the following reaction, C5H12(1) + 8 O2 (g) - 6 H2O (g) + 5 CO2 (g), how many moles of water (H20) are produced by 14.2 moles of O2?

In the following reaction, C5H12(1) + 8 O2 (g) - 6 H2O (g) + 5 CO2 (g), how many moles of water (H20) are produced by 14.2 moles of O2?
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1 vote
In the following reaction, C5H12(1) + 8 O2 (g) - 6 H2O (g) + 5 CO2 (g), how many

moles of water (H20) are produced by 14.2 moles of O2?

asked
User Pete Michaud
by
7.2k points

1 Answer

4 votes

Answer:

10.65 moles

Step-by-step explanation:

O2:H2O

8:6

14.2:x

x= 10.65 moles

answered
User Tronbabylove
by
8.5k points
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