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What is the vertex of f(x)=(x+1)^2-6

What is the vertex of f(x)=(x+1)^2-6
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What is the vertex of f(x)=(x+1)^2-6

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User Mloureiro
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8.2k points

1 Answer

13 votes
(-1, -6) is the vertex of that equation. use the number in the brackets and change the signs for the x-value. use the last number outside of the brackets for the y-value
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User LAW
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