asked 142k views
3 votes
256-x²/4
factorise in process​

asked
User Ayusman
by
7.5k points

1 Answer

4 votes

Answer:


16^2-((x)/(2))^2=(16+(x)/(2))(16-(x)/(2))

Explanation:

The given expression is :
256-(x^2)/(4).

We need to factorize it.

We know that, 16² = 256

So,


256-(x^2)/(4)=(16)^2-((x)/(2))^2

We know that,
a^2-b^2=(a-b)(a+b)


16^2-((x)/(2))^2=(16+(x)/(2))(16-(x)/(2))

Hence, this is the required solution.

answered
User Tron Thomas
by
8.2k points

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