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What is the INITIAL VALUE of the following function?

f(x)=18(1.46)^x

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1 Answer

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Answer:


f(x) = 18(1.46) {}^(x) \\ initially : x = 0 \\ f(0) = 18 * {(1.46)}^(0) \\ = 18

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User Pathik Patel
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