Question

How many formula units (particles of AgNO3) are in 5.50 grams of AgNO3?

(picture for answer choices)

Answer 1

No of molcules(N)= 1.98×10^22

Step-by-step explanation:

m=5.5, Mm= 167, NA= 6.02×10^23

Moles(n)= m/M= N/NA

5.5/167 = N/6.02×10^23

SIMPLIFY

N=1.98×10^22molecules