asked 12.1k views
5 votes
I need help with geometry

I need help with geometry-example-1
asked
User Angerman
by
8.2k points

2 Answers

3 votes

Answer:

Solutions given:

we have

<RTS=PTQ[vertically opposite angle are equal]

so

3x+8=x+20°

3x-x=20-8

2x=12

x=12/2=6

x=6

m<PTQ=6+20=26°

option c.26.

4 votes

9514 1404 393

Answer:

C. 26

Explanation:

The two marked angles are "vertical angles." They are congruent.

x +20 = 3x +8 . . . . . congruent angles have the same measure

12 = 2x . . . . . . . . . subtract x+8 from both sides

6 = x . . . . . . . . . divide by 2

∠PTQ = (x+20)° = (6+20)° = 26°

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