Question

Consider the following reaction:

2CuCl2 + 4KI → 2CuI + 4KCl + I2

When 0.64 grams of CuCl2 reacts with 0.78 grams of KI, how many grams of I2 are formed?











What is the limiting reactant?


What is the excess reactant?
PLEASE I NEED HELP

Answer 1

Your limiting is CuCI2 and the excess is KI (from what i’ve heard from my tc to find it just use the moles or look at the grams)Do you want me to do the qn and give u the ans or?

Explanation:You have more grams of KI than CuCI2
irl example : I need 200g of flour to bake 1 muffin and 100g of butter.But I have 300g of butter and only 200g of flour.This means I can only bake up to 1 muffin since I got excess grams of butter.But to use up all my 300g of butter I need 400g more of flour.Making my butter the excess while my flour the limiting since I have less of it and it also determines how much muffin would I get at the end of the bake.

im sorry if that example sounds clowny T-T