Question

What volume of 9 M sodium hydroxide is required to make 500 mL of 0.1 M sodium hydroxide?

Answer 1

6mL

Step-by-step explanation:

V₁M₁ = V₂M₂

V₁ = V₂M₂/M₁

V₁ = (500)(0.1)/(9)

V₁ = 5.56mL ≈ 6mL