asked 190k views
2 votes
Factorise fully
3y^(3) -12y

2 Answers

3 votes

Answer:


{3y}^(3) - 12y \\ = 3y( {y}^(2) - 4) \\ = 3y( {y}^(2) - {2}^(2) ) \\ = 3y(y - 2)(y + 2) \\ = 3y(y + 2)(y - 2)

answered
User Aldona
by
7.6k points
3 votes

a^2-b^2=(a+b)(a-b)

a=y b=2

3y(y+2)(y-2)

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