Question

What is the value of ſIg(5)) if f(x) = * +2 and g() = x2 – 27

Answer 1

`f(g(5)) = 0`

Explanation:

Given

`f(x) = x+ 2`

`g(x) = x^2 - 27`

Required

`f(g(5))`

First, calculate
`f(g(x))`

We have:

`f(x) = x+ 2`

Substitute
`g(x)` for x

`f(g(x)) = g(x) + 2`

Substitute
`g(x) = x^2 - 27`

`f(g(x)) = x^2 -27+ 2`

`f(g(x)) = x^2 -25`

Substitute 5 for x

`f(g(5)) = 5^2 -25`

`f(g(5)) = 25 -25`

`f(g(5)) = 0`