Question

Find the equation of the circle whose center and radius are given.

center ( -2, -5), radius = 1

Answer 1

(x + 2)^2 + (y + 5)^2 = 1

Explanation:

Since this circle is centered at (-2, -5), we have to add values within the squares. The standard form of a circle equation is:

(x - h)^2 + (y - k)^2 = r^2

So -2 is h and -5 is k. Substituting that in we get:

(x + 2)^2 + (y + 5)^2 = r^2

We are given the radius is 1, and one squared is one, so the final equation is:

(x + 2)^2 + (y + 5)^2 = 1