asked 92.4k views
0 votes
A rectangle has a length of 2x² + 3x +7 and

width of x^2 +5. What is the perimeter of
the rectangle?

2 Answers

4 votes

Answer:


P=6x^2+6x+24

Explanation:


P=2w+2l\\\\w=x^2+5\\\\l=2x^2+3x+7\\\\P=2(x^2+5)+2(2x^2+3x+7)

2 votes

Answer:


perimeter = ( {2x}^(2) + 3x + 7) + ( {x}^(2) + 5) \\ = (3 {x}^(2) + 3x + 12) \: units

answered
User Lonelydatum
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