Question

What is the osmotic pressure in atm of

a 0.50 M urea solution at 25.0°C?
Assume R = 0.0821 Latm/molk
Enter text here

Answer 1

12.2329 atm

Step-by-step explanation:

Applying

PV = nRT.................... Equation 1

Make P the subject of the equation

P = (n/V)RT................ Equation 2

Where P = Osmotic pressure, (n/V) = Molarity of urea, T = Temperature, R = molar gas constant.

From the question,

Given: (n/V) = 0.5 M, T = 25°C = (273+25) = 298 K, R = 0.0821 Latm/mol.K

Substitute these values into equation 2

P = (0.5)(298)(0.0821)

P = 12.2329 atm