Question

A quantity with an initial value of 110 grows continuously at a rate of 0.5% per hour. What is the value of the quantity after 6 hours, to the nearest hundredth?

Answer 1

113.35

Explanation:

Write a function:

f(t)=110e^{rt}

r: grows 0.5%→0.005

f(t)=110e^0.005t

(where t is in hours)

6 hours: no time conversion necessary

Plug in t=6

f(6)=110e^{0.005(6)}

113.349998735

=113.35