Question

What is the molarity of a 1.283 L solution that is made from 16.88 g of NaCl?

Answer in units of M.

Answer 1

0.225M

Step-by-step explanation:

Equation: M=n/v

n = moles of solute

v = liters of solution

NaCl = 58.443 g/mol

16.88/58.443= 0.289 moles of NaCl

0.289/1.283=0.225M