Question

What is an equation of the line that passes through the points (6, -7) and (-6,3)?

Answer 1

y=-5/6x-2

Explanation:

m=(y2-y1)/(x2-x1)

m=(3-(-7))/(-6-6)

m=(3+7)/-12

m=10/-12

simplify

m=-5/6

y-y1=m(x-x1)

y-(-7)=-5/6(x-6)

y+7=-5/6x+30/6

y+7=-5/6x+5

y=-5/6x+5-7

y=-5/6x-2