Question

The initial volume of a gas at a pressure of 3 atm is 5.2 L. What will the volume be if the pressure is increased to 15 atm?

Answer 1

1 L

Step-by-step explanation:

Use Boyle's Law, which is defined as:

p1v1 = p2v2

p1 = 3atm

v1 = 5.2L

p2 = 15atm

v2 = ?

We are solving for v2 because all other variables are given.

p1v1 = p2v2

(3atm)(5.2L) = (15atm)(v2)

v2 = (3)(5.2) / (15) = 1.04 L ≈ 1 L