Question

What is the [OH-] of a substance that has a pH of 11?

Answer 1

0.001 M OH-

Step-by-step explanation:

[OH-] = 10^-pOH, so

pOH + pH = 14 and 14 - pH = pOH

14 - 11 = 3

[OH⁻] = 10⁻³ ; [OH-] = 0.001 M OH-