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For the reaction C + 2H2 → CH4, how many moles of hydrogen are needed to make 108.6 grams of methane, CH4 ?

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Answer:


RFM \: of \: methane \: = 16 \: g \\ 16 \: g \: are \: weighed \: by \: 1 \: mole \: of \: methane \\ 108.6 \: g \: are \: weighed \: by \: ( (108.6)/(16) * 1) \: moles \\ = 6.7875 \: moles \: of \: methane \\ from \: the \: equation : \\ 1 \: mole \: of \: methane \: is \: formed \: by \: 2 \: moles \: of \: hydrogen \\ 6.7875 \: moles \: of \: methane \: will \: be \: produced \: by \: (6.7875 * 2) \: moles \\ = 13.6 \: moles \: of \: hydrogen

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User Igor Bubelov
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