A 17.98-g piece of iron absorbs 2056.5 joules of heat energy, and its temperature changes from 25°C to 200°C. Calculate the specific heat capacity of iron.

Question

asked Dec 24, 2022 43.8k views

1 Answer

Angelo Vargas · Answer 1 · 2022-12-29T03:55:55+0000

Answer:
$0.65\ J/g.^(\circ)C$

Step-by-step explanation:

Given

Mass of iron piece is
$m=17.98\ g$

Heat absorbed
$Q=2056.5\ J$

Temperature changes from
$25^(\circ)C\ to\ 200^(\circ)C$ i.e.

$\Delta T=200-25=175^(\circ)C$

Heat absorbed is given by
$Q=mc\Delta T\quad [c=\text{specific heat of material}]$

Insert the values

$\Rightarrow 2056.5=17.98* c* 175\\\\\Rightarrow c=(2056.5)/(3146.5)\\\\\Rightarrow c=0.65\ J/g.^(\circ)C$

Thus, the specific heat of iron is
$0.65\ J/g.^(\circ)C$