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What is the mole fraction of each component of a gas mixture that contains sulfur trioxide at a pressure of 1.45 atm and sulfur dioxide at a pressure of .32 atm

asked
User Andrei
by
7.6k points

1 Answer

5 votes

Answer:


x_(SO_3)=0.82\\\\x_(SO_2) =0.18\\

Step-by-step explanation:

Hello there!

In this case, according to the given information, it is possible for us to solve this problem by using the Dalton's law which allows us to calculate the mole fractions by dividing the partial pressures over the total pressure. In such a way, we plug in the given pressures of sulfur trioxide (SO3) and sulfur dioxide (SO2) to obtain:


x_(SO_3)=(1.45atm)/(1.45atm+0.32atm) =0.82\\\\x_(SO_2)=(0.32atm)/(1.45atm+0.32atm) =0.18\\

Best regards!

answered
User Zhang Chao
by
8.3k points
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