Question

Given: BD bisects AC and ∠CBE≅∠ADE.

Prove: ABCD is a parallelogram.
add the reason as well pls

Answer 1

Here

• BC=AD(Parallel)
• <BEC=<AEC
• <CBE=<ADE

So

∆BEC
`\cong`∆AED(ASA)

Also similarly

• ∆ABE
  `\cong`∆CBE

Hence it's a paralleogram