Question

Which is the equation of a line that has a slope of -2/3 and passes through point
(–3, –1)?

Answer 1

y=-2/3x-3

Explanation:

y-y1=m(x-x1)

y-(-1)=-2/3(x-(-3))

y+1=-2/3(x+3)

y=-2/3x-6/3-1

y=-2/3x-2-1

y=-2/3x-3