Question

A cylindrical water tank with radius 2 feet and length 6 feet is filled with water to a depth of 3 feet when in a horizontal position. If the tank is turned upright, what is the depth of the water? Give your answer in terms of n.​

Answer 1

That measure to congruent 8 and side angle is 3.9

The correct answer is: m<8 and angle 7.9

Answer 2

The calculated depth of the water when tured upright is 4.5 feet

How to determine the depth of the water when tured upright

From the question, we have the following parameters that can be used in our computation:

Radius = 2 ft

Length = 6 ft

Depth = 3 ft

The base area of the cylinder when bent horizontally is

Area = 3/4πr²

So, we have

Area = 3/4π * 2²

Area = 3π

So, the volume is

Volume = Base area * Height

Volume = 3π * 6

Volume = 18π

At the upright position, we have the volume to be

Volume = πr²h

So, we have

πr²h = 18π

This gives

π * 2²h = 18π

4h = 18

Evaluate

h = 18/4

h = 4.5

Hence, the depth of the water when tured upright is 4.5 feet