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Numbers 1 to 20 are placed in a bag. Without replacing the first number, what is the probability that the first number drawn will be odd and the second will be even?

Numbers 1 to 20 are placed in a bag. Without replacing the first number, what is the probability that the first number drawn will be odd and the second will be even?
asked 110k views
1 vote
Numbers 1 to 20 are placed in a bag. Without replacing the first

number, what is the probability that the first number drawn will
be odd and the second will be even?

asked
User Jason Swager
by
8.5k points

1 Answer

1 vote

Answer:

Explanation:

odd numbers=10

even numbers=10

P=10/20×10/19=5/19

answered
User AshMenhennett
by
8.3k points
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