asked 80.2k views
1 vote
F(x) = 2x^2 - 4x - 5
vertex? (x,y)
number of solutions?
range?

asked
User Kyflare
by
7.3k points

1 Answer

3 votes

Answer:

F(x) = 2x^2 - 4x - 5

vertex? (1,-7)

range?

y>=-7

number of solutions?

Sorry I couldn’t find the answer, I hope this will do.

F(x) = 2x^2 - 4x - 5 vertex? (x,y) number of solutions? range?-example-1
F(x) = 2x^2 - 4x - 5 vertex? (x,y) number of solutions? range?-example-2
answered
User Solopiu
by
8.3k points

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