Question

Find the axis of symmetry and the vertex of
the equation below.
n^2+ 6n = 0

Answer 1

axis of symmerty = x coordinate of vertex = -b/2a

-6/2 = -3 = x

vertex = (-3,y)

-3^2 +6(-3)

9-18 = -9 = y

(-3,-9) = vertex

Explanation: