Question

A laser beam is incident on two slits with a separation of 0.180 mm, and a screen is placed 5.05 m from the slits. If the bright interference fringes on the screen are separated by 1.62 cm, what is the wavelength of the laser light

Answer 1

The answer is "530 nm".

Step-by-step explanation:

`d=0.180 \ nm=0.180 * 10^(-3) \ m\\\\L= 5.05\ m\\\\\Delta y= 1.62\ cm= 1.62 * 10^(-2) \ m\\\\`

Using formula:

`\Delta y=(\lambda L)/(d)\\\\\lambda =(d\Delta y)/(L)\\\\`

`=(0.180 * 10^(-3) * 1.62 * 10^(-2) )/(5.05)\\\\=5.30 * 10^(-9) * (1 \ nm)/(10^(-9) \ m)\\\\=530 \ nm`