Question

a plane rises from take-off and flies at an angle of 6 with the horizontal runway. When it has gained 900 feet, find the distance, to the nearest foot, the plane has flown.

Answer 1

`d=8610.1ft`

Explanation:

From the question we are told that:

Angle
`\theta =6\textdegree`

Height of plane
`h=900ft`

Generally the trigonometric equation for distance flown d is mathematically given by

`sin \theta=(h)/(d)`

Therefore

`d=(h)/(sin\theta)`

`d=(900)/(sin6)`

`d=8610.1ft`